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11. A noted psychic was tested for ESP. The psychic was presented with 200 cards face down and asked to determine if the card was one of five symbols: a star, cross, circle, square, or three wavy lines. The psychic was correct in 50 cases. To determine if he has ESP, we want to know if his success rate is better than someone who just guesses. That is, we test the hypotheses H0: p = 0.20, Ha: p > 0.20, where p represent the proportion of cards for which the psychic correctly identifies the symbol in random trials. Assume the 200 trials described above can be treated as an SRS from the population of all guesses the psychic would make in his lifetime. The P-value of this test is (a) between .10 and .05 (b) between .05 and .025 (c) between .025 and .01 (d) between .01 and .001 (e) below .001 A December 2007 Gallup Poll reported that 43% of Americans use the internet for an hour or more each day. You suspect that a higher proportion of students at your school use the internet that much. To find out, you take a simple random sample of 60 students and find that 35 of them use the internet for an hour or more each day. You will test the hypotheses H0: p = 0.43 and Ha: p > 0.43, where p = the proportion of students at your school who use the internet for an hour or more each day, at the alpha = 0.01 level. 12. Which of the following best describes the sampling distribution of proportions for this test? (a) Mean = 0.583; Standard deviation = 0.064; shape approx. Normal (b) Mean = 0.583; Standard deviation = 0.064; shape unknown (c) Mean = 0.5; Standard deviation = 0.064; shape approx. Normal (d) Mean = 0.43; Standard deviation = 0.064; shape approx. Normal (e) Mean = 0.43; Standard deviation = 0.064; shape unknown 13. The test statistic, P-value, and appropriate decision for this test are; (a) z = 2.40; P-value = 0.008; reject H0 (b) z = 2.40; P-value = 0.008; fail to reject H0 (c) t = 2.40; P-value = 0.0103; reject H0 (d) t = 2.40; P-value = 0.0103; fail to reject H0 (e) no conclusion can be drawn, because the shape of the sampling distribution is unknown.

          11. A noted psychic was tested for ESP. The psychic was presented with 200 cards face down and asked to determine if the card was one of five symbols: a star, cross, circle, square, or three wavy lines. The psychic was correct in 50 cases. To determine if he has ESP, we want to know if his success rate is better than someone who just guesses. That is, we test the hypotheses H0: p = 0.20, Ha: p > 0.20, where p represent the proportion of cards for which the psychic correctly identifies the symbol in random trials. Assume the 200 trials described above can be treated as an SRS from the population of all guesses the psychic would make in his lifetime. The P-value of this test is
(a) between .10 and .05
(b) between .05 and .025
(c) between .025 and .01
(d) between .01 and .001
(e) below .001

A December 2007 Gallup Poll reported that 43% of Americans use the internet for an hour or more each day. You suspect that a higher proportion of students at your school use the internet that much. To find out, you take a simple random sample of 60 students and find that 35 of them use the internet for an hour or more each day. You will test the hypotheses H0: p = 0.43 and Ha: p > 0.43, where p = the proportion of students at your school who use the internet for an hour or more each day, at the alpha = 0.01 level.
12. Which of the following best describes the sampling distribution of proportions for this test?
(a) Mean = 0.583; Standard deviation = 0.064; shape approx. Normal
(b) Mean = 0.583; Standard deviation = 0.064; shape unknown
(c) Mean = 0.5; Standard deviation = 0.064; shape approx. Normal
(d) Mean = 0.43; Standard deviation = 0.064; shape approx. Normal
(e) Mean = 0.43; Standard deviation = 0.064; shape unknown

13. The test statistic, P-value, and appropriate decision for this test are;
(a) z = 2.40; P-value = 0.008; reject H0
(b) z = 2.40; P-value = 0.008; fail to reject H0
(c) t = 2.40; P-value = 0.0103; reject H0
(d) t = 2.40; P-value = 0.0103; fail to reject H0
(e) no conclusion can be drawn, because the shape of the sampling distribution is unknown.

11. A noted psychic was tested for ESP. The psychic was presented with 200 cards face down and asked to determine if the card was one of five symbols: a star, cross, circle, square, or three wavy lines. The psychic was correct in 50 cases. To determine if he has ESP, we want to know if his success rate is better than someone who just guesses. That is, we test the hypotheses H0: p = 0.20, Ha: p > 0.20, where p represent the proportion of cards for which the psychic correctly identifies the symbol in random trials. Assume the 200 trials described above can be treated as an SRS from the population of all guesses the psychic would make in his lifetime. The P-value of this test is
(a) between .10 and .05
(b) between .05 and .025
(c) between .025 and .01
(d) between .01 and .001
(e) below .001

A December 2007 Gallup Poll reported that 43% of Americans use the internet for an hour or more each day. You suspect that a higher proportion of students at your school use the internet that much. To find out, you take a simple random sample of 60 students and find that 35 of them use the internet for an hour or more each day. You will test the hypotheses H0: p = 0.43 and Ha: p > 0.43, where p = the proportion of students at your school who use the internet for an hour or more each day, at the alpha = 0.01 level.
12. Which of the following best describes the sampling distribution of proportions for this test?
(a) Mean = 0.583; Standard deviation = 0.064; shape approx. Normal
(b) Mean = 0.583; Standard deviation = 0.064; shape unknown
(c) Mean = 0.5; Standard deviation = 0.064; shape approx. Normal
(d) Mean = 0.43; Standard deviation = 0.064; shape approx. Normal
(e) Mean = 0.43; Standard deviation = 0.064; shape unknown

13. The test statistic, P-value, and appropriate decision for this test are;
(a) z = 2.40; P-value = 0.008; reject H0
(b) z = 2.40; P-value = 0.008; fail to reject H0
(c) t = 2.40; P-value = 0.0103; reject H0
(d) t = 2.40; P-value = 0.0103; fail to reject H0
(e) no conclusion can be drawn, because the shape of the sampling distribution is unknown.

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