Question

p1 = 6 Mpa 1 T1 = 600 °C V?1 = 0.15 m³/s H2O W?T = 2 MW Q? Tambient = 27 °C 2 p2 = 20 kPa x2 = 0.95

          p1 = 6 Mpa 1
T1 = 600 &deg;C
V?1 = 0.15 m&sup3;/s
H2O
W?T = 2 MW
Q?
Tambient = 27 &deg;C
2 p2 = 20 kPa
x2 = 0.95

p1 = 6 Mpa 1
T1 = 600 deg;C
V?1 = 0.15 m sup3;/s
H2O
W?T = 2 MW
Q?
Tambient = 27 deg;C
2 p2 = 20 kPa
x2 = 0.95

Added by Sebastian A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

07/10/2023

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15 m3/s Wr=2 MW H,O Show more…

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A non-adiabatic turbine operates at steady-state. H2O enters at 6 MPa and 600 degrees C at a volumetric flow rate of 15 m^3/s and exits at 20 kPa with a quality of 95%. The power output from the turbine is 2 MW. Neglect changes in PE and KE. Sufficiently far from the turbine, the surroundings are at a uniform and constant 27 degrees C. Find the rate of entropy generation (kW/K) for a control volume that includes the turbine and enough of the surroundings such that all heat transfer occurs at 27 degrees C.