00:01
Hello students, we have to explain the mechanism of a reaction in this question.
00:06
This is the reaction that is given to us.
00:08
So, first we have been given this substrate which contains a pyridine group here and this pyridine contains a cyanide and here is a ester group.
00:31
So, treatment of this molecule with a base will cause the hydrolysis which will convert this ester to acid like this and here was our pyridine part.
00:53
This cyanide will be hydrolyzed to the amide group.
00:58
So, this will be the structure that will be formed from the given reaction.
01:07
Now in the next step, this amine can attack as a nucleophile on this carbonyl carbon and dehydration will take place due to which this ring will undergo a cyclization like this.
01:29
Here will be c double bond o.
01:31
Both these carbonyls will be joined now by nh group and here is our 5 membered ring which contains a hydroxyl group.
01:42
So, this is how first step will be completed.
01:45
Now let's carry out the reaction of second step.
02:18
This molecule is treated with pcc.
02:22
Now pcc is pyridinium chlorochromate.
02:27
So, this is an oxidizing agent which will oxidize this hydroxyl group into a carbonyl group.
02:34
So, we will get a carbonyl group formed here and here we have this pyridine group which contains a carbonyl group.
02:50
So, this is a pyridine group and here is another carbonyl linked together by nh...