00:01
Let's solve the given question.
00:02
So, as according to the question, we are having, so, data, according to data, q1 is equals to n plus 1 divided 4 is equals to 9 divided 4 is equals to 2 .25.
00:14
So, now, we get q1 is equals to second plus 0 .25 multiply third minus second.
00:25
So, as according to this, 0 .12 plus 0 .25 multiply 0 .2 minus 0 .12 is equals to 0 .14.
00:36
Now, the q3 is equals to n plus 1 multiply 3 divided 4 is equals to 27 divided 4 is equals to 6 .75.
00:46
So, then q3 is equals to 6 plus 0 .75 multiply 7 minus 6.
00:54
So, it is equals to 1 plus 0 .75 multiply 2 minus 1.
00:59
So, we get it equals to 1 .75.
01:03
So, as according to this, therefore, iqr is equals to q3 minus q1 is equals to 1 .75 minus 0 .14 which is equals to 1 .61.
01:21
So, as according to this, lower q1 minus 1 .5 multiply iqr is equals to the 0 .14 minus 1 .5 multiply 1 .61 is equals to 2 .275 and now we find the upper value that is equals to q1 plus 1 .5 multiply iqr is equals to 0 .14 plus 1 .5 multiply 1 .61 which is equals to 4 .165.
02:03
So, now as we can see that there are no outliers.
02:11
So, as to be according to this, we find mean is equals to summation of x divided n is equals to 7 .97 divided 8 is equals to the 0 .99625...