A page fault must be preceded by a TLB miss. True False
Added by Jonathan A.
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- TLB (Translation Lookaside Buffer): A small, fast-access memory that stores recently used virtual-to-physical address translations. - Page fault: An event that occurs when a running program accesses a memory page that is not currently mapped by the memory Show more…
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'When a Page Fault is encountered during Virtual Address translation to Physical Address; either only hardware or only software can be used to handle the page fault: True False'
Muhammad J.
Operating Systems Using a TLB A TLB is used with the memory system above: (s1, s2, p) Frame address 0 4 16 52 Which of the following addresses will find a match in the TLB: 0, 1, 2, 3, 4, 9, 16, 17, 52, 64, 65, 66. Which of these addresses cause a page fault? Which result in an error? a) 0 and 16 b) 1,2,3,4,9,17,52,64,65,68 causes page faults. Virtual memory uses paging and segmentation. The segment table also paged. Non-resident pages are kept on disk Physical memory Page table of segment table Disk Block # Contents A virtual address has the form (s1,s2,p,w) where each component is 2 bits. The page table of the paged segment table starts at address 32. A dash denotes a nonexistent page or page table. A positive number, n, in a table means that the page currently resident in memory starting at address n. A negative number, -n, in a table means that the page is not resident in memory and must be loaded from the disk. The value of n then gives the disk block containing the missing page. Ex: A -2 in a page table entry indicates that the page is not in main memory and can be found in disk block 2.
Akash M.
1. When a running process experiences a page fault, the frame to hold the missing page can only come from those frames allocated to that process, not from frames used by any other process. The memory system chooses which frame to use using a simple first-in first-out technique. That is, the first time it must choose a frame to use to hold a page being loaded to resolve a page fault, it chooses the first frame it loaded originally. The second page fault then uses the now ‘oldest’ frame (the second one that had been loaded originally), and so on: the first frame (originally) loaded becomes the first frame ‘out’ (i.e., to be reused). Each page fault causes only the one missing page to be loaded. Now suppose a program is executing a straight, linear sequence of instructions that is 100 Kbytes long. This process is allocated 20 frames, each 4 Kbytes big, when put into memory. How many page faults will there be to completely execute this sequence of instructions? BONUS problem: Finally, suppose the 100 Kbyte block of instructions is a loop that repeats infinitely. How many page faults are there on the second iteration of the loop?
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