00:01
In this problem, we are given that there are two dice and these two dice are tossed.
00:07
And we are required to find the probability that the doubles are rolled and it's given that the sum on the two dice that is less than 11.
00:21
So we will consider two events here.
00:24
Event e, that's the event of rolling doubles.
00:29
So in this case, the outcomes which should be favorable to this event e, that would be same numbers which are peering on the two dice.
00:39
And we see that there are six outcomes which is favorable to this event e.
00:44
And the total number of outcomes, that would be six times six because we know that when a dice is rolled, we have six possible outcomes.
00:52
And let's consider the event f as the event of getting the sum, which is less than 11.
01:02
So the outcomes which would be favorable to this event f, that could be all the outcomes except the one in which we get the sum as 11 and the sum as 12.
01:16
So we see that the sum 12 is obtained only when we get six on both dice and sum of 11 is obtained when we get five on the first, six on the second or six on the first and five on the second...