A parallel-plate capacitor has a plate area of 0.3 m^2 and a plate separation of 0.1 mm. If the charge on each plate has a magnitude of 5 x 10^-6 C then the force exerted by one plate on the other has a magnitude of about: 5 N 0 9 N 1 x 10^4 N 9 x 10^5 N
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- The area of the plates (A) is 0.3 m². - The separation between the plates (d) is 0.1 mm, which is 0.1 x 10^-3 meters (since 1 mm = 10^-3 meters). - The magnitude of the charge on each plate (Q) is 5 x 10^-6 C (Coulombs). Show more…
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