Question

A parallel-plate capacitor has a plate area of 169 cm^2 and a plate separation of 0.0400 mm. a) Determine the capacitance. The permittivity of a vacuum is 8.85419e-12 C^2/N x m^2. Answer in units of F. b) Determine the potential difference when the charge on the capacitor is 450.0 pC. Answer in units of V.

Name: a parallel plate capacitor has a plate area of 169 cm2 and a plate separation of 00400 mm a determine the capacitance the permittivity of a vacuum is 885419e 12 c62n x m2 answer in units of 24502
Uploaded: 2022-04-19T12:38:16-08:00
Duration: 1 min 51 s
Channel: Prabhu Ramji
Description: a parallel plate capacitor has a plate area of 169 cm2 and a plate separation of 00400 mm a determine the capacitance the permittivity of a vacuum is 885419e 12 c62n x m2 answer in units of 24502

          A parallel-plate capacitor has a plate area of 169 cm^2 and a plate separation of 0.0400 mm.
a) Determine the capacitance. The permittivity of a vacuum is 8.85419e-12 C^2/N x m^2. Answer in units of F.
b) Determine the potential difference when the charge on the capacitor is 450.0 pC. Answer in units of V.

Added by Donald A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

04/19/2022

Step 1

69 x 10^-4 m^2 Plate separation, d = 0.0400 mm = 0.0400 x 10^-3 m Permittivity of vacuum, ε₀ = 8.85419 x 10^-12 C^2/N x m^2 Show more…

Show all steps

Thanks for your feedback!

A parallel-plate capacitor has a plate area of 169 cm^2 and a plate separation of 0.0400 mm. a) Determine the capacitance. The permittivity of a vacuum is 8.85419e-12 C^2/N x m^2. Answer in units of F. b) Determine the potential difference when the charge on the capacitor is 450.0 pC. Answer in units of V.