Question

A parallel-plate capacitor has plates of area A = 250 cm^2 and separation d = 2.00 mm. The capacitor is charged to a potential difference ΔV0 = 140 V. Then the battery is disconnected (fixing the charge Q on the plates), and a dielectric sheet (κ = 3.60) of the same area A but thickness l = 1.00 mm is fully inserted between the plates. Calculate the fraction of the stored energy that is stored in the electric field inside the dielectric.

Name: a parallel plate capacitor has plates of area a250 cm2 and separation d200 mm the capacitor is charged to a potential difference v0140 v then the battery is disconnected fixing the charge q 73127
Uploaded: 2023-03-31T12:19:53-08:00
Duration: 6 min 49 s
Channel: Ivan Kochetkov
Description: a parallel plate capacitor has plates of area a250 cm2 and separation d200 mm the capacitor is charged to a potential difference v0140 v then the battery is disconnected fixing the charge q 73127

          A parallel-plate capacitor has plates of area A = 250 cm^2 and separation d = 2.00 mm. The capacitor is charged to a potential difference ΔV0 = 140 V. Then the battery is disconnected (fixing the charge Q on the plates), and a dielectric sheet (κ = 3.60) of the same area A but thickness l = 1.00 mm is fully inserted between the plates. Calculate the fraction of the stored energy that is stored in the electric field inside the dielectric.

Added by Crystal T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

03/31/2023

Step 1

First, we need to find the capacitance of the capacitor without the dielectric. The formula for the capacitance of a parallel-plate capacitor is: $C_0 = \frac{\epsilon_0 A}{d}$ where $\epsilon_0 = 8.85 \times 10^{-12} \, \text{F/m}$ is the vacuum permittivity, Show more…

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A parallel-plate capacitor has plates of area A = 250 cm^2 and separation d = 2.00 mm. The capacitor is charged to a potential difference ΔV0 = 140 V. Then the battery is disconnected (fixing the charge Q on the plates), and a dielectric sheet (κ = 3.60) of the same area A but thickness l = 1.00 mm is fully inserted between the plates. Calculate the fraction of the stored energy that is stored in the electric field inside the dielectric.