00:01
In this problem, we have been given a function that's going to tell us the price of a crop perversial at a time t.
00:11
And we are being asked to find the relative rate of change, the percentage rate of change at t equals zero, t equals one, and t equals two.
00:24
All right.
00:25
So we're not being asked over intervals to do that.
00:28
We're being asked to do that at a specific value.
00:30
In order to do that, we need the derivative.
00:32
So we take the derivative of f of t, the derivative of 6, is zero because it's a constant.
00:37
The derivative of 0 .005t is just 0 .005.
00:41
And then the derivative of 0 .05e to the negative t is going to be the derivative of negative t, which is negative 1, times 0 .05e to the negative t, because the derivative of e to the x is e to the x...