00:01
So in this problem, we're told that a person's starting salary is $27 ,500, and that every year they're going to get a raise of $1 ,500 per year.
00:10
So in part of this problem, we want to determine their salary after six year.
00:15
So essentially, what we can do is we can tweak the $27 ,500, and we continuously add $1 ,500.
00:21
Well, that would mean we're going to be using a geometric or an arithmetic sequence, because to get from one term to the next, we're adding a constant.
00:29
So in this case, we can use our formula to find any term in the arithmetic sequence.
00:34
It's a sub n equals a sub 1 plus d times n minus 1.
00:39
Well, n is the number of terms in this, which in this case is going to equal to 6.
00:44
So we're going to have a sub 6.
00:46
A sub 1 is the first term, which in this case is the southern salary of $27 ,500.
00:52
And then d, that represents what we're adding to get from one term to next.
00:56
So that would be our raise, which is $1 ,500, times.
01:00
N, we already mentioned, was 6 minus 1.
01:03
So now we just need to simplify.
01:05
So we're going to a sub 6 equal to 27 ,500.
01:08
Then we have 6 minus 1, which is 5, and 1 ,500 times 5 is 7500...