A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels a distance 1 S in the first 10 sec and a distance 2 S in the next 10 sec, then
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Step 1
Given, S = 1, t = 10 sec Using the equation S = ut + (1/2)at^2, where a is the acceleration, 1 = u(10) + (1/2)a(10)^2 1 = 10u + 50a 10u = 1 - 50a u = (1 - 50a) / 10 Show more…
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A body moves along a straight line with constant acceleration for $20 \mathrm{~s}$ after it starts from rest. It covers a distance $\mathrm{S}$ in the first 10 seconds and $\mathrm{S}$, in the next 10 seconds of its motion. Relation between $\mathrm{S}_{1}$ and $\mathrm{S}_{2}$ is (a) $\mathrm{S}_{2}=3 \mathrm{~S}_{1}$ (b) $\mathrm{S}_{2}=4 \mathrm{~S}_{1}$ (c) $\mathrm{S}_{2}=2 \mathrm{~S}_{1}$ (d) $\mathrm{S}_{2}=\mathrm{S}_{1}$
A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels a distance S1 in the first 10 sec and a distance S2 in the next 10 sec, then find the relation between s1 and s2
Aakash G.
"1. A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels a distance in the first 10 sec and a distance in the next 10 sec, then"
Dharmendra M.
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