A particle is executing simple harmonic motion with an amplitude of 0.02 metre and frequency 50 Hz. The maximum acceleration of the particle i
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02 m Frequency (f) = 50 Hz Show more…
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A particle is executing simple harmonic motion with an amplitude of $0.02$ metre and frequency $50 \mathrm{~Hz}$ The maximum acceleration of the particle is: (a) $100 \mathrm{~m} / \mathrm{s}^{2}$ (b) $100 \pi^{2} \mathrm{~m} / \mathrm{s}^{2}$ (c) $100 \pi \mathrm{m} / \mathrm{s}^{2}$ (d) $200 \pi^{2} \mathrm{~m} / \mathrm{s}^{2}$
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