A particle is moving along X axis . The position of the particle at any instant is given by X =5 + 6t square , where X is in meters , t in seconds . What is the velocity of the particle at t = 2s?
Added by Juan Carlos H.
Step 1
The position function is given by: X(t) = 5 + 6t^2 Now, let's find the derivative of X(t) with respect to t: v(t) = dX/dt = d(5 + 6t^2)/dt Using the power rule for differentiation, we get: Show more…
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