00:01
Hello students, in this question the radius of the circular path r is given as 4 cm and the speed of the particle is given as 1 cm per second.
00:13
We have to find time period.
00:20
Time period t is given by the formula 2 pi by omega.
00:25
Here omega is equal to v over r.
00:28
So we can substitute t is equal to 2 pi r divided by substituting all the known values we get 2 into 3 .14 into 4 divided by 1.
00:48
Time period t will be equal to 25 .13 seconds.
00:56
Next we have to find the average speed of the particle.
01:05
Since the speed is constant throughout the motion average speed will be equal to the constant speed which is equal to 1 cm per second.
01:40
Next we have to find the average velocity for the time interval t by 4.
01:50
Let us consider the motion of the particle in the circular path.
01:58
Let us consider the initial position of the particle to be a and the final position after t by 4 will be b.
02:06
Since we know this is a circle both the length will be the radius of the circular path.
02:13
From this we can say the displacement will be the line joining the a and b which is nothing but the hypotenuse of the right angle triangle aob.
02:24
From this we can say by pythagoras theorem s square will be equal to r square plus r square.
02:45
So we can say s square will be equal to 2r square...