A particle is moving on a circular path. The angle turned by the radius vector is (1 - e - t/3), where theta is in radians and t is in seconds. The angular acceleration at t = 0 is A. 10 rad/s^2 B. 1/3 rad/s^2 C. -1/9 rad/s^2 D. -1/6 rad/s^2
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The angle \(\theta\) is given by the function \(\theta(t) = 1 - e^{-t/3}\). Show more…
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