00:01
As students, we are given a particle position function, okay? we just need to solve abc part.
00:04
So what we are given, st is equals to t -q minus 70 square plus 11 -t minus 2 .5.
00:13
We are asked in the first part, we just need to find the velocity and acceleration function.
00:18
Okay, so we are supposed to know that we can be written as ds by dt.
00:22
Okay, so v comes out as equal to the derivation of this term.
00:26
So 3t square, okay, and after that minus 7, 2 is a 14.
00:30
So 14 t plus 11 and we are supposed to know that the acceleration is nothing but equal to d b by d t.
00:37
So a comes out as equals to 3 to just 6 so 60 minus 14.
00:41
Okay.
00:42
Those are the terms.
00:44
Now we will go for the b part.
00:46
What we are asked to find the times when the particle is at rest...