A particle moves along the x-axis. Its position is given by the equation x = 1.5 + 2.7t - 3.6t^2 with x in meters and t in seconds. (a) Determine its position when it changes direction. (b) Determine its velocity when it returns to the position it had at t = 0? (Indicate the direction of the velocity with the sign of your answer.)
Added by Peter M.
Step 1
This occurs when the final velocity is zero, so we set the final velocity equation to zero: \[V_f = V_i + at = 0\] \[2.7 - 7.2t = 0\] Solving for t: \[t = \frac{2.7}{7.2} = 0.375 \text{ seconds}\] Show more…
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