A particle of charge $q$ moves in a circular path of radius $r$ perpendicular to a uniform magnetic field $B$. Determine its linear momentum in terms of the quantities given.
Added by David R.
Step 1
Step 1: The centripetal force acting on the charged particle is given by \( F_{\text{centripetal}} = \frac{mv^2}{r} \). Show more…
Show all steps
Your feedback will help us improve your experience
Suman K and 88 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
(II) A particle of charge $q$ moves in a circular path of radius $r$ in a uniform magnetic field $B .$ Show that its momentum is $p=q B r .$
A particle of charge $q$ and mass $m$ is accelerated from rest through a potential difference $V$, after which it encounters a uniform magnetic field $B$. If the particle moves in a plane perpendicular to $B$, what is the radius of its circular orbit?
(II) For a particle of mass $m$ and charge $q$ moving in a circular path in a magnetic field $B,(a)$ show that its kinetic energy is proportional to $r^{2},$ the square of the radius of curvature of its path, and (b) show that its angular momentum is $L=q B r^{2},$ about the center of the circle.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD