00:01
In this problem, we have been given that there is a particle of mass m which is released from point a.
00:08
And as it is released, its initial velocity will be zero meter per second.
00:13
And the track that's shown here, that is a frictionless track.
00:18
So here we are required to determine the speed at point b and the speed of particle at point c.
00:26
So first we will do that.
00:27
And we are going to use work energy theorem, according to which the network done.
00:33
That's the change in kinetic energy.
00:36
And reversibly, we can also apply the energy conservation.
00:40
So we observe that the total energy at point a, that is just the gravitational potential energy.
00:46
So between a and b, we observe that the difference in height, that is 1 .8 meters.
00:53
So the change in gravitational potential energy will give rise to the kinetic energy of the particle at point b.
01:01
So this implies that half m into vb square, it's equal to mg times the difference in height that's 5 minus 3 .2.
01:10
So m gets cancelled and let's substitute g as 9 .81 meter per second square and this is going to get us the speed at point b as 5 .94 meter per second...