A particle of mass M at rest splits into two other particles, of masses m1 and m2, which go in opposite directions with speeds 5c/13 and 12c/13 respectively. Calculate m1 and m2.
Added by Gabriel A.
Step 1
Since they are going in opposite directions, we can write: p1 = -p2 So, we have: 0 = p_before = p_after = p1 - p1 = 2p1 Therefore, the momentum of each particle after the split is: p1 = p2 = 0 Show more…
Show all steps
Your feedback will help us improve your experience
Christian Dell and 57 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A stationary particle explodes into two particles of a masses m1 and m2 which move in opposite directions with velocities 1 v and . 2 v The ratio of their kinetic energies E1/E2 ?
Krishna J.
Two particles of masses M1 = 40000 kg and M2 = 2300 kg are initially at rest an infinite distance apart. As a result of the gravitational force the two masses move towards each other. Calculate the speed of mass M1 when their separation distance is 32.5 km. Calculate the speed of mass M2 at this separation distance.
Sri K.
Two equal masses $m_{1}$ and $m_{2}$ moving along the same straight line with velocities $+3 \mathrm{~m} / \mathrm{s}$ and $-5 \mathrm{~m} / \mathrm{s}$ respectively collide elastically. Their velocities after the collision will be respectively $(a]+4 \mathrm{~m} / \mathrm{s}$ for both (b) $-3 \mathrm{~m} / \mathrm{s}$ and $+5 \mathrm{~m} / \mathrm{s}$ (c) $-4 \mathrm{~m} / \mathrm{s}$ and $+4 \mathrm{~m} / \mathrm{s}$ (d) $-5 \mathrm{~m} / \mathrm{s}$ and $+3 \mathrm{~m} / \mathrm{s}$
Centre of Mass
Round 1
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Watch the video solution with this free unlock.
EMAIL
PASSWORD