00:01
In this given problem initial speed or we can say velocity, initial velocity of the particle along x -axis that is given as v -i -x, which is 5 .1 meter per second.
00:26
And there was no initial velocity along y -axis so that will be taken as zero and its acceleration in vector form that is minus 3 .1 i cap which is along x -axis plus 5 .0 j cap which is along y -axis the moment it will achieve it will reach to the maximum possible x -axis means for the maximum x -coordinate because as it is clear due to this negative acceleration its velocity along x -axis is going on reducing so at one stage it will come moving forward along x -axis so for the maximum x coordinate its final velocity along x -axis that should be equal to zero.
01:36
So to find this time taken for the velocity along x -axis to be equal to zero, to become equals to zero, using first equation of motion vfx is equal to v ix plus a x t.
01:55
So this is 0 here.
01:58
This is 5 .1 acceleration that is minus 3 .1 into t.
02:05
So time taken to go up to the maximum possible x coordinate that will be given by 5 .1 divided by 3 .1 second.
02:16
And here this time will come out to be equal to 1 .64 second.
02:23
Now, in this first part of the problem, we have to find the velocity achieved by this particle, then it will reach up to the maximum possible x coordinate.
02:35
So, it will be having both the components.
02:38
Vertical component means component of velocity along y -axis as well as along x -axis...