Question

A particle with a charge of $-5.90$ nC is moving in a uniform magnetic field of $\vec{B} = -(1.24 \text{ T})\hat{k}$. The magnetic force on the particle is measured to be $\vec{F} = -(4.00 \times 10^{-7} \text{ N})\hat{i} + (7.60 \times 10^{-7} \text{ N})\hat{j}$.

Name: A particle with a charge of -5.90 nC is moving in a uniform magnetic field of B⃗ = -(1.24 T)k̂. The magnetic force on the particle is measured to be F⃗ = -(4.00 × 10^-7 N)î + (7.60 × 10^-7 N)ĵ.
Uploaded: 2023-08-31T18:23:27-08:00
Duration: 1 min 34 s
Channel: Sri K
Description: A particle with a charge of -5.90 nC is moving in a uniform magnetic field of B⃗ = -(1.24 T)k̂. The magnetic force on the particle is measured to be F⃗ = -(4.00 × 10^-7 N)î + (7.60 × 10^-7 N)ĵ.

          A particle with a charge of $-5.90$ nC is moving in a uniform magnetic field of $\vec{B} = -(1.24 \text{ T})\hat{k}$. The magnetic force on the particle is measured to be $\vec{F} = -(4.00 \times 10^{-7} \text{ N})\hat{i} + (7.60 \times 10^{-7} \text{ N})\hat{j}$.

A particle with a charge of -5.90 nC is moving in a uniform magnetic field of B⃗ = -(1.24 T)k̂. The magnetic force on the particle is measured to be F⃗ = -(4.00 × 10^-7 N)î + (7.60 × 10^-7 N)ĵ.

Added by Felix N.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

08/31/2023

Step 1

The formula is given by the equation F = q*v*B*sin(theta), where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field, and theta is the angle between the velocity and the magnetic field. Show more…

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A particle with a charge of -5.90nC is moving in a uniform magnetic field of vec(B)=-(1.24T)hat(k). The magnetic force on the particle is measured to be vec(F)=-(4.00 imes 10^(-7)(N))hat(i)+(7.60 imes 10^(-7)(N))hat(j). A particle with a charge of -5.90 nC is moving in a uniform magnetic field of B=-1.24 Tk.The magnetic force on the particle is measured to be F=-4.00x10-7Ni+7.60x10-7Nj