A particle with charge $-3.00 \mathrm{nC}$ is at the origin, and a particle with negative charge of magnitude $Q$ is at $x=50.0 \mathrm{cm} .$ A third particle with a positive charge is in equilibrium at $x=20.9 \mathrm{cm} .$ What is $Q$ ?
Added by Wendy K.
Step 1
00 \, \text{nC}}{(0.209 \, \text{m})^2} = \frac{K \cdot Q}{(0.500 \, \text{m} - 0.209 \, \text{m})^2}\] Show more…
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