A particular fruit's weights are normally distributed, with a mean of 337 grams and a standard deviation of 38 grams. If you pick 5 fruit at random, what is the probability that their mean weight will be between 296 grams and 316 grams
Added by Kenia R.
Step 1
The mean of this distribution is the same as the mean of one fruit, which is 337 grams. The standard deviation of this distribution is the standard deviation of one fruit divided by the square root of the number of fruits, which is sqrt(5). So, the standard Show more…
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