A particular fruit's weights are normally distributed, with a mean of 506 grams and a standard deviation of 21 grams. If you pick one fruit at random, what is the probability that it will weigh between 475 grams and 565 grams? The heaviest 5% of fruits weigh more than how many grams?
Added by Amy T.
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To find the z-score, we use the formula: z = (x - μ) / σ where: x = the given weight μ = the mean weight σ = the standard deviation For 475 grams: z1 = (475 - 506) / 21 = -31 / 21 = -1.476 For 565 grams: z2 = (565 - 506) / 21 = 59 / 21 = 2.810 Show more…
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