Question

A particular fruit's weights are normally distributed, with a mean of 748 grams and a standard deviation of 16 grams. If you pick 3 fruit at random, what is the probability that their mean weight will be between 742 grams and 751 grams

          A particular fruit's weights are normally distributed, with a mean of 748 grams and a standard deviation of 16 grams.
If you pick 3 fruit at random, what is the probability that their mean weight will be between 742 grams and 751 grams

A particular fruit's weights are normally distributed, with a mean of 748 grams and a standard deviation of 16 grams.
If you pick 3 fruit at random, what is the probability that their mean weight will be between 742 grams and 751 grams

Added by Beatriz S.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Qudsiya Anis

06/23/2023

Step 1

SEM = standard deviation / sqrt(sample size) SEM = 16 / sqrt(3) SEM ≈ 9.24 grams Show more…

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A particular fruit's weights are normally distributed, with a mean of 748 grams and a standard deviation of 16 grams. If you pick 3 fruit at random, what is the probability that their mean weight will be between 742 grams and 751 grams A particular fruit's weights are normally distributed, with a mean of 748 grams and a standard deviation of 16grams. If you pick 3 fruit at random, what is the probability that their mean weight will be between 742 grams and 751grams