00:02
In this problem, the given data is that power of heater, that is ph is equal to 2 .4 kilowatt hour.
00:17
Now, power of light bulb, that is, pl is equal to 100 watt, that is 0 .1 kilowatt watt.
00:33
And power of electric stove that is pe is equal to 2 .5 kilowatt -r and miscellaneous power that is pm is 2 .3 kilowatt -r per day.
01:02
Now we have to calculate daily energy use heater that that is ph is equal to 2 .4 kilowatt into 2 hours per day which is equal to 4 .8 kilowatt then daily energy uses of light bulbs of light bulbs that is pl is equal to 4 multiply 0 .1 kilowatt watt into 7 hour per day that is 2 .8 kilowatt hour then daily energy uses of electric stove that is pe is equal to 2 .5 kilowattr into 1 .0 r per day which is equal to 2 .5 kilowatt r into 1 .0 r per day which is equal to 2 .5.
02:21
Kilowatt hour.
02:24
Now total daily energy uses of household, households.
02:39
That is, it becomes p total, that is 4 .8 plus 2 .8 plus 2 .8 plus 2 .3, which is equal to 12 .7 kilowatt now we are given electricity cost in first part electricity cost is dollar 0 .105 per kilowatt hour and total monthly electric bill, electric bill, that is monthly bill is equal to monthly bill is equal to monthly will is equal to 12 .7 kilowatt r into dollar 0 .105 per kilowatt hour into 30 days equal to dollar 40 .005.
03:55
Now in second part we have to calculate cold, total amount of cold, that is, given quantity is 7005.
04:09
Kilo calorie per k .g...