A passenger on an interplanetary express bus traveling at v = 0.98 c takes a 4.0-minute catnap, according to her watch. How long does her catnap from the vantage point of a fixed planet last? **SHOW WORK**
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The formula is given by: \[ \Delta t' = \frac{\Delta t}{\sqrt{1 - \frac{v^2}{c^2}}} \] where: \( \Delta t' \) = time interval observed in the moving frame (4.0 minutes in this case) \( \Delta t \) = time interval observed in the stationary frame (what we need to Show more…
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