00:02
Hi, for this problem, we are giving the properties of a pelting wheel.
00:07
We are told the radius of the wheel is 1 .83 meters.
00:13
The velocity of the jet is 102 meters per second.
00:19
The nozzle diameter is 10 centimeters.
00:26
Beta is 165 degrees.
00:33
And here, beta is the turning angle of the bucket.
00:39
And of course the density of water which we know i'll just write that 1 ,000 kilograms can meet a key.
00:49
The first question says we should find the volume flow rate.
00:58
The volume flow rate is simply equal to the area of the nozzle times the jet velocity and that will be pi over 4 times the diameter of the nozzle squared times the jet velocity.
01:16
Now we have all these variables so i will simply plug them in 5 over 4 times 10 centimeters and this will give me 0 .801 meters cube per second.
01:44
The second part asks us to find the optimum rotation rate of the wheel.
02:02
Now for a pelting wheel, we know that for maximum power output, for maximum power output, the speed of the buckets must equal half the speed of the jet.
02:28
And so what is the speed of the buckets? it simply pi times the diameter of the buckets times n all over 60.
02:42
N is the rotation rate.
02:45
And we are told that this must be equal to 1 over 2 times the jet velocity...