Question

A perimeter fence around a dangerous device has a height of 1325 mm. The dangerous device has a height of 2150 mm, and the horizontal distance from the device to the fence is 550 mm. The company policy specifies that all perimeter fences can be designed using the standard specifications.

          A perimeter fence around a dangerous device has a height of 1325 mm. The dangerous device has a height  of 2150 mm, and the horizontal distance from the device to the fence is 550 mm. The company policy  specifies that all perimeter fences can be designed using the standard specifications.
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A perimeter fence around a dangerous device has a height of 1325 mm. The dangerous device has a height of 2150 mm, and the horizontal distance from the device to the fence is 550 mm. The company policy specifies that all perimeter fences can be designed using the standard specifications.
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Transcript

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00:01 All right, hello, in this question we're told you want to build a fence along a house.
00:03 So i have my house over here.
00:06 I'll just say this is house.
00:09 I want to build a fence over here with dimensions x by y.
00:12 And i'm told that the area of this garden, the area of the fence region, is going to be 1050 feet squared.
00:19 I want to determine the dimensions that minimize the fencing material, providing this sketch.
00:26 So this would be my sketch.
00:28 I know my area is going to equal x times y, which equals 1050.
00:34 That's my constraint function.
00:35 So i'm going to go ahead and solve that for y, because i want to optimize the perimeter.
00:40 So my perimeter function, i'm going to have x plus 2y.
00:44 That's just the amount of fencing required for the three side.
00:47 They don't have to build a fence along the house.
00:49 And so i can go ahead and plug in my constraint function here.
00:53 So i'm going to have x plus 2100 over x.
00:59 And that will be my fence perimeter function.
01:02 I want to optimize that.
01:03 So i'm going to take a derivative.
01:04 I'll get 1 minus 2100 over x squared.
01:07 Set that equal to 0 and solve.
01:09 Well, x is going to be plus or minus the square root of 2100.
01:14 The minus doesn't make sense here, because this has to be a physical thing.
01:17 It has a length.
01:18 And so i don't want a negative length...
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