Question

A person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 "g's." A) Calculate the magnitude of the force on a 66-kg person accelerating at this rate. B) What distance is traveled if brought to rest at this rate from 120 km/h ?

Name: a person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 gs a calculate the magnitude of the force on a 66 kg person accelerating at this rate 89194
Uploaded: 2022-04-18T03:13:57-08:00
Duration: 3 min 3 s
Channel: Suman K
Description: a person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 gs a calculate the magnitude of the force on a 66 kg person accelerating at this rate 89194

          A person has a reasonable chance of surviving an automobile
crash if the deceleration is no more than 30 "g's."
A) Calculate the magnitude of the force on a 66-kg person
accelerating at this rate.
B) What distance is traveled if brought to rest at this rate
from 120 km/h ?

Added by Eugenia B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Suman K

04/18/2022

Step 1

8 m/s^2 Acceleration, a = 30 * g = 30 * 9.8 = 294 m/s^2 Using Newton's second law, F = m * a F = 66 kg * 294 m/s^2 F = 19404 N Show more…

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A person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 "g's." A) Calculate the magnitude of the force on a 66-kg person accelerating at this rate. B) What distance is traveled if brought to rest at this rate from 120 km/h ?