Question

A seesaw of length 2L is balanced at its center. A person of mass m is sitting at a distance x from the center. A mass M is placed at the end of the seesaw. The supports exert upward forces $R_1$ and $R_2$. Find the values of $R_1$, $R_2$, and x in terms of m, M, and L.

Name: A seesaw of length 2L is balanced at its center. A person of mass m is sitting at a distance x from the center. A mass M is placed at the end of the seesaw. The supports exert upward forces R1 and R2. Find the values of R1, R2, and x in terms of m, M, and L.
Uploaded: 2022-01-04T08:58:10-08:00
Duration: 3 min 12 s
Channel: Prabhu Ramji
Description: A seesaw of length 2L is balanced at its center. A person of mass m is sitting at a distance x from the center. A mass M is placed at the end of the seesaw. The supports exert upward forces R1 and R2. Find the values of R1, R2, and x in terms of m, M, and L.

          A seesaw of length 2L is balanced at its center. A person of mass m is sitting at a distance x from the center. A mass M is placed at the end of the seesaw. The supports exert upward forces $R_1$ and $R_2$. Find the values of $R_1$, $R_2$, and x in terms of m, M, and L.

A seesaw of length 2L is balanced at its center. A person of mass m is sitting at a distance x from the center. A mass M is placed at the end of the seesaw. The supports exert upward forces R1 and R2. Find the values of R1, R2, and x in terms of m, M, and L.

Added by Edwin P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

01/04/2022

Step 1

The forces acting vertically are the weight of the person (mg), the weight of the board (Mg), and the reaction forces at the supports (R1 and R2). The equation for equilibrium of forces in the vertical direction is: R1 + R2 - mg - Mg = 0 Show more…

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A person of mass m stands at a distance x from the end of a board of length L and mass M as shown.i) write down two equations, one for equlibrium of forces( in the vertical) and one for equilibrium of moments about the right hand end ii) if m=50kg, M=150kg, L= 6m and x = 3m, find the values of R1,R2 R1 1 R2 * 6ut 6W t X 7 -