Question

A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 591 N. As the elevator later stops, the scale reading is 391 N. Assuming the magnitude of the acceleration is the same during starting and stopping, determine: (a) The weight of the person (b) The person's mass (c) The acceleration of the elevator

Name: a person stands on a scale in an elevator as the elevator starts the scale has a constant reading of 591n as the elevator later stops the scale reading is 391n assuming the magnitude of the 48086
Uploaded: 2021-03-02T21:45:59-08:00
Duration: 2 min 43 s
Channel: Eric Mockensturm
Description: a person stands on a scale in an elevator as the elevator starts the scale has a constant reading of 591n as the elevator later stops the scale reading is 391n assuming the magnitude of the 48086

          A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 591 N. As the elevator later stops, the scale reading is 391 N. Assuming the magnitude of the acceleration is the same during starting and stopping, determine:
(a) The weight of the person
(b) The person's mass
(c) The acceleration of the elevator

Added by Lisa A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Eric Mockensturm

03/02/2021

Step 1

Given: Force on scale during starting = 591 N Force on scale during stopping = 391 N Using the equation F_net = ma in the vertical direction: 591 N - W = m*a 391 N - W = -m*a Where W is the weight of the person, m is the mass of the person, and a is the Show more…

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A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 591 N. As the elevator later stops, the scale reading is 391 N. Assuming the magnitude of the acceleration is the same during starting and stopping, determine: (a) The weight of the person (b) The person's mass (c) The acceleration of the elevator