Question

A person swimming underwater on a bright day and looking up at the surface will see a bright circle surrounded by relative darkness shown below, a phenomenon known as Snell’s window. The index of refraction of water is nwater = 1.33. (10 points) What is the angle of Snell’s window: θ ?

          A person swimming underwater on a bright day and looking up at the surface will see a bright circle surrounded by relative darkness shown below, a phenomenon known as Snell’s window. The index of refraction of water is nwater = 1.33. (10 points) What is the angle of Snell’s window: θ ?
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A person swimming underwater on a bright day and looking up at the surface will see a bright circle surrounded by relative darkness shown below, a phenomenon known as Snell’s window. The index of refraction of water is nwater = 1.33. (10 points) What is the angle of Snell’s window: θ ?
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Transcript

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00:01 Hello everybody here it is the air medium and it is the water medium and light is falling from air to the water and diver is inside the water at this point and the maximum angle is theta till which he can see the light coming from here now that means light should fall parallel to this surface so that it gets refracted to this diver at an angle theta and at this point diver will not be able to see any light.
00:44 If light is refracted more than this angle theta, driver will not be able to see any light.
00:52 So from nell's law, we say that sine theta divided by sine 90 degree is equal to to mu that is the refractive index, mu air, refractive index of air divided by mu water that is refractive index of water.
01:24 Now why we have put this sine 90 degree? because light was falling parallel to the surface.
01:33 So sine theta is equal to 1 divided by 1 .33...
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