Question

A person's blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. The balanced equation is 16H+(aq) + 2Cr2O7^2-(aq) + C2H5OH(aq) → 4Cr3+(aq) + 2CO2(g) + 11H2O(l). If 35.46 mL of 0.05961 M Cr2O7^2- is required to titrate 30.90 g of plasma, what is the mass percent of alcohol in the blood? _____mass%

Name: a persons blood alcohol c2h5oh level can be determined by titrating a sample of blood plasma with a potassium dichromate solution the balanced equation is 16haq 2cr2o72aq c2h5ohaq 4cr3aq 2co 82223
Uploaded: 2022-05-22T23:13:34-08:00
Duration: 1 min 13 s
Channel: David Collins
Description: a persons blood alcohol c2h5oh level can be determined by titrating a sample of blood plasma with a potassium dichromate solution the balanced equation is 16haq 2cr2o72aq c2h5ohaq 4cr3aq 2co 82223

          A person's blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. The balanced equation is 16H+(aq) + 2Cr2O7^2-(aq) + C2H5OH(aq) → 4Cr3+(aq) + 2CO2(g) + 11H2O(l). If 35.46 mL of 0.05961 M Cr2O7^2- is required to titrate 30.90 g of plasma, what is the mass percent of alcohol in the blood? _____mass%

Added by Teresa L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

05/22/2022

Step 1

Given: 35.46 mL of 0.05961 M Cr2O7^2- 35.46 mL = 35.46/1000 L = 0.03546 L Show more…

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A person's blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. The balanced equation is 16H+(aq) + 2Cr2O7^2-(aq) + C2H5OH(aq) → 4Cr3+(aq) + 2CO2(g) + 11H2O(l). If 35.46 mL of 0.05961 M Cr2O7^2- is required to titrate 30.90 g of plasma, what is the mass percent of alcohol in the blood? _____mass%