00:02
Firstly, we have to draw the figure as according to the question, there are the pipes.
00:08
Different pipes are being there such that the diagram should be like this.
00:18
So this is part two, part one, part three.
00:22
This is half pipe.
00:25
This is three in pipe and this is two in pipe.
00:31
So now given data is low density is 892 kg, meter is square.
00:38
Also du upon dt is equals to 1 .388 into 10 is to the power minus 3.
00:46
So du upon dt will be a1 and v1 where a is the cross section and v is the speed at the point a.
00:56
So db upon dt will be a1 v1 is equals to a2 b2 multiply 2.
01:04
So diameter d1 is given to us which is 0.
01:08
0 .0508 meter also d2 is 0 .381 meter this can be 2 inch and this can be 1 .5 inch so next according to the a we have dm upon d t is equals to pay a 2 v2 at point now dm upon d t this is row even v1 at point 1 at point 3 at point 1 so 892 multiply pi d1 upon 2 square and v1 so we'll put the values whatever we have this will be pi d1 upon 2 v1 which is equals to dv upon d t so this is 892 multiply 1 .38 into 10x through the power minus 3.
02:18
So we get 1 .23800.
02:25
So dm upon dt at 0 .3 row a2 v2 minus row by 2 dv upon dt.
02:37
This will be 0 .6194.
02:43
Now for the b1 or the v1 we have dv upon d t...