A photon has the energy $5.55 imes 10^{-19}$ J. What is this photon's wavelength in nanometers? a. 590 nm b. $3.58 imes 10^{-5}$ pm c. 358 nm d. 222 nm
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We can use the formula: E = hf where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 Js), and f is the frequency of the photon. We can rearrange the formula to solve for the frequency: f = E / h Now, we can plug in the given energy: f = Show more…
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