A physiological saline solution contains $154 \mathrm{mEq} / \mathrm{L}$ each of $\mathrm{Na}^{+}$ and $\mathrm{Cl}^{-}$. How many moles each of $\mathrm{Na}^{+}$ and $\mathrm{Cl}^{-}$ are in $1.00 \mathrm{~L}$ of the saline solution?
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00 L of the saline solution. Given that the concentration of Na+ is 154 mEq/L, we can convert this to moles by multiplying by the molar mass of Na+ (23 g/mol): Number of moles of Na+ = 154 mEq/L * (1 mol / 1000 mEq) = 0.154 mol/L Since we have 1.00 L of the Show more…
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