A pickup truck has a wheelbase of 3.00 m. Ordinarily,...

A pickup truck has a wheelbase of $3.00 \mathrm{~m}$. Ordinarily, $10,780 \mathrm{~N}$ rests on the front wheels and $8820 \mathrm{~N}$ on the rear wheels when the truck is parked on a level road. (a) $\mathrm{A}$ box weighing $3600 \mathrm{~N}$ is now placed on the thilgate, $1.00 \mathrm{~m}$ behind the rear axle. How much totul weight now rests on the front wbeels? On the rear wheels? (b) How much weight would need to be placed on the tailgute to make the front wheels come off the ground?

Transcript

00:01 Hi, in this question the wheel base of a truck is given as 3 meters.

00:06 This is the front wheel and this is the rear wheel.

00:09 The wheel base is the distance between the front wheel and the rear wheel, which is given as 3 meters.

00:15 So l is equal to 3 meters.

00:18 The reaction force at the front wheel is given as 10 ,780 newton.

00:22 The reaction at the rear wheel is given as 8 ,820 newtons.

00:27 Then the weight of the box placed at a distance of 1 meter from the rear wheel is given as 3 ,600 newtons.

00:36 And this weight, this is the box, this box is weighing 3 ,600 newtons which is kept at a distance of 1 meter from the rear wheel.

00:50 And this distance, let us say, from the rear wheel, this is the center of gravity, of the truck before placing this box.

01:03 This is the distance x -barr.

01:06 X -bore is the distance between the central gravity of the truck and the rear wheel.

01:12 We need to determine the total weight on the front wheels.

01:16 Also we need to find the amount of weight that can be placed on the tailgate to make the front wheels come off the ground.

01:26 That means this force, that is the force, the total force, are the total weight acting on the front wheel.

01:34 After that we need to determine the magnitude of the load that can be placed on the tailgate.

01:42 How much load that can be placed here? now 3 ,600 newton has been placed and how much can be placed so that this front wheel comes off the ground.

01:53 That is what we need to determine.

01:55 So first of all, let us determine the distance between the rear wheel and the central gravity of the truck, that is x -bore.

02:04 X -bore is equal to the 10 ,780, 10 ,780, which is acting at a distance of 3 meters, plus this 8 ,820, multiply with the distance between the rear wheel and the rear wheel is 0.

02:29 Divided by the total weight, that is 10 ,780 plus 8 ,820.

02:42 On calculation we obtained, the x -bar value is equal to 1 .65 meters.

02:55 So, this distance from the rear wheel to the central graphic of the truck is 1 .65 meters.

03:02 Now let us take the moments about the rear wheels to determine the total weight...

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