Question

A piece of metal that weighs 0.356 kg was heated to 85.0 °C and then put it into 70.2 mL of water (initially at 26.7 °C). The metal and water were allowed to come to an equilibrium temperature, determined to be 17.8 °C. Assuming no heat lost to the environment, calculate the specific heat of the metal. 

          A piece of metal that weighs 0.356 kg was heated to 85.0 °C and then put it into 70.2 mL of water (initially at 26.7 °C). The metal and water were allowed to come to an equilibrium temperature, determined to be 17.8 °C. Assuming no heat lost to the environment, calculate the specific heat of the metal.
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A piece of metal that weighs 0.356 kg was heated to 85.0 °C and then put it into 70.2 mL of water (initially at 26.7 °C). The metal and water were allowed to come to an equilibrium temperature, determined to be 17.8 °C. Assuming no heat lost to the environment, calculate the specific heat of the metal.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Transcript

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00:02 High, when 0 .356 kg of metal at a higher temperature is added to water at lower temperature, then the metal lose some of its heat which is ultimately gained by this water.
00:15 Therefore, heat lost by metal is equal to the heat gained by water.
00:23 Now the formula to calculate the heat lost by metal is m, c multiplied by delta t.
00:30 Here, m is the mass of metal, cm is the specific heat capacity of the metal, and delta t is the change in the temperature of metal.
00:40 And the heat gained by water is mw, this is mass of water, heat capacity of water, and the temperature change of water.
00:52 Now the mass of water is given as 0 .356 kg.
00:56 In grams, we can say it is 356 grams.
01:00 Therefore, 356 grams.
01:04 The specific heat capacity of metal is what we need to find out in this question.
01:10 Now the final temperature of the resulting solution is 17 .8 degrees celsius minus initial temperature is 85 degrees celsius.
01:25 Mass of water is not given but volume is 72mm.
01:31 We know density of water is 1 .0 grams.
01:34 Per m .n.
01:36 Therefore, mass of water is calculated as density multiplied by volume...
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