00:01
Hello students, in this question for the first part of the question we have to find the work done by the piston.
00:05
For that we need to find the specific volume of the saturated liquid at 150 degree celsius.
00:11
We know that from steam table vf is equal to 0 .00109 meter cube per kilogram and vg will be equal to 0 .3928 meter cube per kilogram.
00:28
We know that from the first law of thermodynamics delta u is equal to q minus w.
00:46
Since the process is isothermal we can say delta u is equal to 0.
01:00
Substituting we get q is equal to w.
01:05
So in this case heat transfer will be equal to work done.
01:11
We have to find the specific work.
01:13
W will be equal to vf, vg, vdv.
01:20
We know that at 150 degree celsius pressure will be equal to 4 .76 bar which is equal to 476 kilo pascal.
01:32
So in this case pressure remains a constant.
01:38
So the specific work will be equal to p into vg minus vf which is equal to 476 kilo pascal into 0 .3928 minus 0 .00109 meter cube per kilogram...