Question

A piston cylinder has 2.2 kg of air at 300 K and 150 kPa. It is now heated up in a two step process. First constant volume to 1000 K (state 2) then followed by a constant pressure process to 1500 K, state 3. Find the final volume and final pressure. (R of air = 0.287 KJ/kg K)

Name: a piston cylinder has 22 kg of air at 300 k and 150 kpa it is now heated up in a two step process first constant volume to 1000 k state 2 then followed by a constant pressure process to 1500 92898
Uploaded: 2023-06-24T17:44:06-08:00
Duration: 2 min 35 s
Channel: Adi S
Description: a piston cylinder has 22 kg of air at 300 k and 150 kpa it is now heated up in a two step process first constant volume to 1000 k state 2 then followed by a constant pressure process to 1500 92898

          A piston cylinder has 2.2 kg of air at 300 K and 150 kPa. It is now heated up in a two step process. First constant volume to 1000 K (state 2) then followed by a constant pressure process to 1500 K, state 3. Find the final volume and final pressure.   (R of air = 0.287 KJ/kg K)

Added by James C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/24/2023

Step 1

2\,\text{kg})(0.287\,\text{kJ/kg}\cdot\text{K})(300\,\text{K})}{150\,\text{kPa}} = 1.24\,\text{m}^3$ Since the process is constant volume, $V_2 = V_1 = 1.24\,\text{m}^3$. Now, we can find the pressure at state 2 using the ideal gas law: $P_2 = \frac{mRT_2}{V_2} Show more…

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A piston cylinder has 2.2 kg of air at 300 K and 150 kPa. It is now heated up in a two step process. First constant volume to 1000 K (state 2) then followed by a constant pressure process to 1500 K, state 3. Find the final volume and final pressure. (R of air = 0.287 KJ/kg K)