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Hello guys, in this problem, we cover a concept of projectile motion.
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In this problem, we have a plane.
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The plane is moving with speed of 40 meters per second, and it is given that the altitude of the plane above the ground is 100 meter.
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The brain drops a package.
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When the plane drops the package, the initial velocity of the package is equivalent to the velocity of the plane, that is 40 meters per second in horizontal.
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And the acceleration of the package is vertically downward, that is acceleration due to gravity.
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As the packet falls, it also move forward.
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And let's suppose it hit the ground at this point.
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Now assume the spot on the ground just below the point of projection as origin.
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And let's assume in the vertical upper direction y -axis and along horizontal axis.
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Now we can write.
01:06
The displacement along vertical equals the initial velocity in vertical into the time of travel t minus half times acceleration due to gravity times t square when the package falls on the ground the displacement equals negative of the initial height that is altitude of the plane the initial vertical velocity is zero minus half g t square hence the time of flight that is the time after which the package hit the ground is square root of two times the height of the plane over acceleration due to gravity.
01:48
For the first part, let's substitute the values...