A planet has twice the mass and twice the radius of the Earth. What is the free-fall acceleration on the surface of that planet (in terms of Earth's value of g)? a. g b. 2g c. g/2 d. g/4
Added by James O.
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If the planet has twice the mass of Earth, then M = 2M_earth. If the planet has twice the radius of Earth, then r = 2r_earth. Substituting these values into the formula, we get g_planet = G(2M_earth)/(2r_earth)^2 = GM_earth/r_earth^2 = g_earth. So, the Show more…
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