A planet of mass m = 1.15 Ă— 10^24 kg is orbiting in a circular path around a star of mass M = 1.45 Ă— 10^29 kg. The radius of the orbit is R = 7.45 Ă— 10^7 km. What is the orbital period (in Earth days) of the planet Tplanet?
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67 \times 10^{-11} \, \text{m}^3 \, \text{kg}^{-1} \, \text{s}^{-2} \), \( m_{planet} = 1.15 \times 10^{24} \, \text{kg} \), \( m_{star} = 1.45 \times 10^{29} \, \text{kg} \), and \( r = 7.45 \times 10^{7} \, \text{km} \). Show more…
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