Question

A planet orbits a star. The distance from the star to this planet is 791 million km. The time for the planet to orbit once is measured to be 261.1 years, What is the period of this planet in Seconds? Round ONE place past the decimal Use Scientific Notation: On Blackboard $6.67 \times 10^{-11}$ is written 6.67E-11, another example: $3 \times 10^8$ is written: 3E8

          A planet orbits a star. The distance from the star to this planet is 791 million km. The time for the planet to orbit once is measured to be 261.1 years,
What is the period of this planet in Seconds? Round ONE place past the decimal
Use Scientific Notation: On Blackboard $6.67 \times 10^{-11}$ is written 6.67E-11, another example: $3 \times 10^8$ is written: 3E8

A planet orbits a star. The distance from the star to this planet is 791 million km. The time for the planet to orbit once is measured to be 261.1 years,
What is the period of this planet in Seconds? Round ONE place past the decimal
Use Scientific Notation: On Blackboard 6.67 × 10^-11 is written 6.67E-11, another example: 3 × 10^8 is written: 3E8

Added by Steven F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

07/17/2023

Step 1

1 kilometer is equal to 1000 meters. So, to convert 791 million kilometers to meters, we multiply by 1000. 791 million km * 1000 m/km = 791 billion meters Show more…

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A planet orbits a star. The distance from the star to this planet is 791 million km. The time for the planet to orbit once is measured to be 261.1 years. What is the period of this planet in seconds? Round one place past the decimal. Use Scientific Notation. On Blackboard, 6.67x10^-11 is written as 6.67E-11. Another example, 3x10^8 is written as 3E8.