00:01
In this question, we will calculate the surface charge density in the inner surface for part a.
00:10
Q1 is equal to 4 times 10 density of the power minus 6.
00:15
A is equals to 2 times 10th to the power minus 2.
00:21
Now for first part, the magnitude of total charge on the inner surface will be equal to the charge at the center of the sphere q1.
00:27
Since q1 is negative, the induced charge on the inner surface will be positive.
00:31
Hence, the charge density of the inner surface, i'm calling it sigma 1.
00:36
Minus q1 over 4 pi a square putting the values 4 times 10 to the power minus 6 over 4 pi times 2 times 10 to the power minus 2 simplifying this gives 7 .96 times 10 to the power minus 4 coulum per meter square this will be the answer for the first part for second part sigma 2 service charge density on the outer side surface.
01:27
That will be first of all, since the total charge on the conductor should be equal to the initial charge that is to u -culum, the induced charge in the inner surface will cause an opposite charge to be induced in the surface to the conductor...