Question

A point charge q1 = +2.40 μC is held stationary at the origin. A second point charge q2 = -4.30 μC moves from the point x = 0.140 m, y = 0, to the point x = 0.255 m, y = 0.255 m. a) What is the change in potential energy of the pair of charges? b) How much work is done by the electric force on q2?

Name: a point charge q1240uc is held stationary at the origin a second point charge q2 430uc moves from the point x0140m y0 to the point x0255m y0255ma what is the change in potential energy of th 97379
Uploaded: 2022-08-05T18:04:57-08:00
Duration: 2 min 12 s
Channel: Timothy James
Description: a point charge q1240uc is held stationary at the origin a second point charge q2 430uc moves from the point x0140m y0 to the point x0255m y0255ma what is the change in potential energy of th 97379

          A point charge q1 = +2.40 μC is held stationary at the origin. A second point charge q2 = -4.30 μC moves from the point x = 0.140 m, y = 0, to the point x = 0.255 m, y = 0.255 m.

a) What is the change in potential energy of the pair of charges?
b) How much work is done by the electric force on q2?

Added by Amanda D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Timothy James

08/05/2022

Step 1

Given: Initial potential energy, U_initial = -0.663 J Final potential energy, U_final = -0.2576 J Use the formula for change in potential energy: ΔU = U_final - U_initial Show more…

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A point charge q1 = +2.40 μC is held stationary at the origin. A second point charge q2 = -4.30 μC moves from the point x = 0.140 m, y = 0, to the point x = 0.255 m, y = 0.255 m. a) What is the change in potential energy of the pair of charges? b) How much work is done by the electric force on q2?