00:03
So, we are given that poker player is dealt three spades, three spades and two hearts.
00:13
He discarded two hearts and draws another true, okay, draws the two more cards.
00:23
So what is the probability that he draws two more spades? so let's get started to solution.
00:30
So let me remind you first.
00:31
The concept which we are going to use here for this question.
00:36
Let's suppose we are having a number of things and we want to select our number of object out of that.
00:41
So this can be given by the formula of combination n factorial divided by n minus of r factorial multiply by r factorial.
00:50
Now same thing is happening here.
00:51
See we remember 52 deck of cards will be there.
00:59
Now out of that a three sped spate.
01:03
And 2 hertz is already discarded so 3 plus a 2 will be how much 5 so 5 card already discarded that means 52 minus 5 will become 7 equals to 47 so only remaining how many cards 47 cards so we just can write it down in the sentence like player is having 3 spades and 2 hertz so now there are are 47 cards in the deck, 47 cards in the deck, because already we have taken out the 5 cards, 3 spats and 2 hurts.
01:51
So out of which, out of which, that is 13 minus 3 is 10 are nothing but of spades, clear? because we remember out of 52 cards total spades cars are 13...